Hickory Grove Township, Benton County, Indiana

Hickory Grove Township
Township

Location of Hickory Grove Township in Benton County
Coordinates: 40°31′06″N 87°28′47″W / 40.51833°N 87.47972°W / 40.51833; -87.47972Coordinates: 40°31′06″N 87°28′47″W / 40.51833°N 87.47972°W / 40.51833; -87.47972
Country United States
State Indiana
County Benton
Organized March 1876
Government
 • Type Indiana township
Area
 • Total 28.9 sq mi (75 km2)
 • Land 28.9 sq mi (75 km2)
 • Water 0 sq mi (0 km2)
Elevation[1] 745 ft (227 m)
Population (2010)
 • Total 409
 • Density 14.2/sq mi (5.5/km2)
Time zone EST (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 18-33358[2]
GNIS feature ID 453410

Hickory Grove Township is one of eleven townships in Benton County, Indiana. As of the 2010 census, its population was 409 and it contained 172 housing units.[3] It was organized in March 1876 and named for a grove of hickory trees that grew within its borders in the 19th century.[4]

Geography

According to the 2010 census, the township has a total area of 28.9 square miles (75 km2), all land.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains one cemetery, Totheroh.

References

  1. ↑ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
  3. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.
  4. ↑ Birch, Jesse Setlington (1942) [1928]. History of Benton County and Historic Oxford. Oxford, Indiana: Craw & Craw, Inc. p. 21.
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